Asked by Danny
                The actual heat of formation of MgO is -601.8 kJ/mol. Convert this to kcal/mol and calculate your % error. And list two possible sources of procedural error to account for this percentage. 
            
            
        Answers
                    Answered by
            DrBob222
            
    -601 kJ/mol x (1 kcal/4.184 kJ) = ? kcal/mol.
%error = (actual value-experimental value/actual value)*100 = ??
You're on your own for the rest of it; we don't know how the experiment was conducted.
    
%error = (actual value-experimental value/actual value)*100 = ??
You're on your own for the rest of it; we don't know how the experiment was conducted.
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.