Asked by priya
Calculate the heat of formationof benzene if the heat of combustion of benzene is 3260 kj/mol, given the following enthalpies of formation of the product.
enthalpies of formation for O2= 0k (element)
enthalpies of formation CO2 = -394kj/mol
enthalpies of formation H2O= -285 kJ/mol
enthalpies of formation for O2= 0k (element)
enthalpies of formation CO2 = -394kj/mol
enthalpies of formation H2O= -285 kJ/mol
Answers
Answered by
DrBob222
Write the equation and balance it.
2C6H6 + 15O2 ==> 12CO2 + 6H2O
DHrxn = (n*DHfproducts) - (n*DHfreactants)
Divide by 2 to find the DHf for one mole.
2C6H6 + 15O2 ==> 12CO2 + 6H2O
DHrxn = (n*DHfproducts) - (n*DHfreactants)
Divide by 2 to find the DHf for one mole.
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