Asked by Elisa

Acid spills are often neutralized with sodium carbonate. For example
Na2CO3 (s) + H2SO4 (aq)  Na2SO4 (aq) + CO2 (g) + H2O (l)
An instructor dropped a 2.50 L bottle of 18.0 M H2SO4 on a cement floor. How much sodium carbonate would be required to neutralize it?
Answered by DrBob222
How many moles do you have in the spilled H2SO4? That is
2.50L x 18.0 M = approximately 50 moles.
So you will need how many moles Na2CO3. Look at th equation. It's 1 mole Na2CO3 for 1 mol H2SO4; therefore, we will need about 50 (you need to do it more accurately.)
50 mols x molar mass Na2CO3 = grams
Answered by Anonymous
5300
Answered by Anonymous
36
Answered by hamburger
0.09
Answered by Anonymous
4.77 kg
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