Asked by candy
21) The number of oil spills occurring off the Alaskan coast
A) Discrete B) Continuous
Find the odds.
22) When a single card is drawn from an ordinary 52-card deck, find the odds in favor of getting a red 10 or a black 6.
A) 2: 25 B) 1 : 13 C) 1 : 25 D) 1 : 12
23) If the probability that an identified hurricane will make a direct hit on a certain stretch of beach is 0.01, what are the odds against a direct hit?
A) 98: 1 B) 99 : 1 C) 100 : 1 D) 1 : 100
Solve the problem.
24) The odds in favor of a storm are 4 to 1. What is the probability that a storm will occur?
A) 4 B) C) D)
Find the odds.
25) Two cards are drawn without replacement from an ordinary deck of 52 playing cards. What are the odds in favor of drawing two queens?
A) 1 : 220 B) 220 : 1 C) 1 : 168 D) 1 : 221
A) Discrete B) Continuous
Find the odds.
22) When a single card is drawn from an ordinary 52-card deck, find the odds in favor of getting a red 10 or a black 6.
A) 2: 25 B) 1 : 13 C) 1 : 25 D) 1 : 12
23) If the probability that an identified hurricane will make a direct hit on a certain stretch of beach is 0.01, what are the odds against a direct hit?
A) 98: 1 B) 99 : 1 C) 100 : 1 D) 1 : 100
Solve the problem.
24) The odds in favor of a storm are 4 to 1. What is the probability that a storm will occur?
A) 4 B) C) D)
Find the odds.
25) Two cards are drawn without replacement from an ordinary deck of 52 playing cards. What are the odds in favor of drawing two queens?
A) 1 : 220 B) 220 : 1 C) 1 : 168 D) 1 : 221
Answers
Answered by
Writeacher
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Answered by
candy
21.A
22.B
23.B
24.A
25.D
22.B
23.B
24.A
25.D
Answered by
KEL
24.D
Answered by
Reiny
22. number of red tens = 2
number of black 6's = 2
number of your event = 4
prob (red10 or black 6) = 4/52
prob (NOT(red10 or black6)) = 48/52
odds in favour of (red10 or black6) = (4/52) / (48/52)
= 4/48
= 1 : 12
which is D
24. odds in favour of storm = 4 : 1
so prob of storm is 4/5
25.
prob of QQ = (4/52)(3/51) = 1/221
prob not QQ = 220/221
odds in favour of QQ = (1/221) / (220/221)
= 1 : 220
which is A
number of black 6's = 2
number of your event = 4
prob (red10 or black 6) = 4/52
prob (NOT(red10 or black6)) = 48/52
odds in favour of (red10 or black6) = (4/52) / (48/52)
= 4/48
= 1 : 12
which is D
24. odds in favour of storm = 4 : 1
so prob of storm is 4/5
25.
prob of QQ = (4/52)(3/51) = 1/221
prob not QQ = 220/221
odds in favour of QQ = (1/221) / (220/221)
= 1 : 220
which is A
Answered by
nahema
continuous
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