Asked by Missy
a rectangular box has a volume of V(x)=x^3+13x^2+50x+56 cubic inches. The height of the box is x+7 inches. The width of the box is x+4 inches. Find the length of the box in terms of x.
Answers
Answered by
drwls
Divide the cubic equation by (x+7)(x+4), using polynomial long division, or by factoring the cubic.
Hint: In this case, (x+4) and (x+7) are factors of the cubic. Find the third factor.
Second hint:
(x^3 +13x^2 +50x + 56)/(x+4)
= x^2 + 9x + 14
(Now, factor that)
Hint: In this case, (x+4) and (x+7) are factors of the cubic. Find the third factor.
Second hint:
(x^3 +13x^2 +50x + 56)/(x+4)
= x^2 + 9x + 14
(Now, factor that)
Answered by
Megan
x+2 inches
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