LMN have vertices at L(0,4) M(-5,2),and N (2,-2). determine the equation for the perpendicular bisector that passes through MN

Answer 1

M(-5,2), (x,y), N(2,-2).

X = (-5+2) / 2 = -3/2.
Y = (2+(-2)) / 2 = 0.

m1 = (-2-2) / (2-(-5)) = -4/7.
m2 = 7/4 = Negative reciprocal of m1.

(-3/2,0). m2 = 7/4.

Y = mx + b.
(7/4)(-3/2) + b = 0.
b = 21/8.

Eq: Y = (7/4)x + 21/8.