Asked by Amy

I need to write an equation for when the slope is 5/3 and the y-intercept is (0,-3)
I got Y = 5/3x +o
Cn someone verify for me please also i don't know how to find the slope of x=1

Answers

Answered by Bosnian
y = m x + b


m = slope

b = y-intercept


In this case :

slope m = 5 / 3

y-intercept = - 3


y = ( 5 / 3 ) x + ( - 3 )

y = ( 5 / 3 ) x - 3


Answered by Bosnian
Line x = 1

are parallel with y-axis and passing through point x = 1

The angle theta a line makes with the positive x axis is closely related to the slope m via the tangent function:

m = tan ( theta )

In this case theta = 90 °

tan 90 ° = infinity

Slope of line x = 1

m = infinity

Answered by Amy
Thank youuu
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