Asked by Amy
I need to write an equation for when the slope is 5/3 and the y-intercept is (0,-3)
I got Y = 5/3x +o
Cn someone verify for me please also i don't know how to find the slope of x=1
I got Y = 5/3x +o
Cn someone verify for me please also i don't know how to find the slope of x=1
Answers
Answered by
Bosnian
y = m x + b
m = slope
b = y-intercept
In this case :
slope m = 5 / 3
y-intercept = - 3
y = ( 5 / 3 ) x + ( - 3 )
y = ( 5 / 3 ) x - 3
m = slope
b = y-intercept
In this case :
slope m = 5 / 3
y-intercept = - 3
y = ( 5 / 3 ) x + ( - 3 )
y = ( 5 / 3 ) x - 3
Answered by
Bosnian
Line x = 1
are parallel with y-axis and passing through point x = 1
The angle theta a line makes with the positive x axis is closely related to the slope m via the tangent function:
m = tan ( theta )
In this case theta = 90 °
tan 90 ° = infinity
Slope of line x = 1
m = infinity
are parallel with y-axis and passing through point x = 1
The angle theta a line makes with the positive x axis is closely related to the slope m via the tangent function:
m = tan ( theta )
In this case theta = 90 °
tan 90 ° = infinity
Slope of line x = 1
m = infinity
Answered by
Amy
Thank youuu
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