Asked by Reina
Solve for x:
2(27)^x=9^(x+1)
2(27)^x=9^(x+1)
Answers
Answered by
Steve
27 = 3^3
9 = 3^2
2(3^3)^x = (3^2)^(x+1)
2*3^3x = 3^(2x+2)
2 = 3^(2x+2-3x) = 3^(2-x)
log<sub>3</sub>2 = 2-x
x = 2-log<sub>3</sub>2
9 = 3^2
2(3^3)^x = (3^2)^(x+1)
2*3^3x = 3^(2x+2)
2 = 3^(2x+2-3x) = 3^(2-x)
log<sub>3</sub>2 = 2-x
x = 2-log<sub>3</sub>2
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