Asked by Jenny
Express in exponential form:
-3log5(z)-x^2=2x+1
-3log5(z)-x^2=2x+1
Answers
Answered by
Steve
-3log<sub>5</sub>z = (x+1)^2
log<sub>5</sub>z = -(x+1)^2 / 3
z = 5^[-(x+1)^2 / 3] = 1/5^[(x+1)^2 / 3]
log<sub>5</sub>z = -(x+1)^2 / 3
z = 5^[-(x+1)^2 / 3] = 1/5^[(x+1)^2 / 3]
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