Asked by Jenny
Express in logarithmic form:
y=27(1/3)^2x
y=27(1/3)^2x
Answers
Answered by
Steve
ln y = ln 27 + 2x*ln(1/3)
ln y = ln 27 - 2x*ln 3
ln 27 - ln y = 2x ln 3
ln (27/y) = 2x * ln 3
2x = ln(27/y)/ln(3) = log<sub>3</sub>(27/y)
x = 1/2 log<sub>3</sub>(27/y)
ln y = ln 27 - 2x*ln 3
ln 27 - ln y = 2x ln 3
ln (27/y) = 2x * ln 3
2x = ln(27/y)/ln(3) = log<sub>3</sub>(27/y)
x = 1/2 log<sub>3</sub>(27/y)
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