Question

For no apparent reason, a poodle is running counter-clockwise at a constant speed of 3.00 m/s in a circle with radius 2.9. Let v_1 be the velocity vector at time t_1, and let v_2 be the velocity vector at time t_2. Consider \Delta v = v_2-v_1 and \Delta t = t_2 - t_1. Recall that a_av = \Delta v/ \Delta t.

For \Delta t = 0.4s calculate the magnitude (to four significant figures) of the average acceleration a_av.

For \Delta t = 0.4 s calculate the direction (relative to v_1) of the average acceleration a_av.

I was able to solve the first part: a_av = 3.081 m/s^2, but I have no idea how to calculate the second part.

Answer 1

How did you even get 3.081 m/s^2? I don't get it.