Acetic acid is HAc.
mols HAc = 1L x 3M = 3 mols.
..........HAc + OH^- ==> A^- + H2O
initial...3......0.......0.....0
add...............x...............
change.....-x.....-x......x
equil.......3-x....0.......x
Now substitute into Henderson-Hasselbalch equation and solve for for x
pH = pKa + log(base)/(acid)
Help please!
How many moles of NaOH must be added to 1.0 L of 3.0 M HC2H3O2 to produce a solution buffered at each pH?
1) pH= 3.78
2) PH= 6.52
1 answer
1 answer