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Asked by Carol

How many moles of Al are needed to form 2.43 mol of Al2Br6?
5 years ago

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Answered by anonymous
(2.43 mol Al2Br6)*(2 mol Al/ 1 mol Al2Br6)= 4.86 mol Al
5 years ago
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How many moles of Al are needed to form 2.43 mol of Al2Br6?

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