Question

The electric field intensity between two charged plates is 1.1*10^3 N/C. The plates are 0.070 m apart. What is the electric potential difference, in volts, between the plates?

Answer 1

You assume that the field, E, is constant between the plates. Then the force per coulomb charge is the same everywhere between the plates. Then the force times the distance is the potential per coulomb. So E d = V.
1.1 * 10^3 Newtons/coulomb * 0.070 meters = 77 Newton meters/coulomb or Joules/coulomb or Volts