Asked by Chris

A 0.23 kg ball of dough is thrown straight up into the air with an initial velocity of 12 m/s.Find the momentum of the ball of dough halfway to its maximum height on the way up.
Answered by bobpursley
KE at half height=
1/2 m v^2=1/2 (1/2 m 12^2)
or v= sqrt(1/2 144)=sqrt72

momentum at half height:
.23*sqrt72

check that.
Answered by Angela
what is sqrt??
Answered by Rachel
Square Root