Asked by Chris
                A 0.23 kg ball of dough is thrown straight up into the air with an initial velocity of 12  m/s.Find the momentum of the ball of dough halfway to its maximum height on the way up. 
            
            
        Answers
                    Answered by
            bobpursley
            
    KE at half height=
1/2 m v^2=1/2 (1/2 m 12^2)
or v= sqrt(1/2 144)=sqrt72
momentum at half height:
.23*sqrt72
check that.
    
1/2 m v^2=1/2 (1/2 m 12^2)
or v= sqrt(1/2 144)=sqrt72
momentum at half height:
.23*sqrt72
check that.
                    Answered by
            Angela
            
    what is sqrt??
    
                    Answered by
            Rachel
            
    Square Root 
    
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