Asked by Chris
A 0.23 kg ball of dough is thrown straight up into the air with an initial velocity of 12 m/s.Find the momentum of the ball of dough halfway to its maximum height on the way up.
Answers
Answered by
bobpursley
KE at half height=
1/2 m v^2=1/2 (1/2 m 12^2)
or v= sqrt(1/2 144)=sqrt72
momentum at half height:
.23*sqrt72
check that.
1/2 m v^2=1/2 (1/2 m 12^2)
or v= sqrt(1/2 144)=sqrt72
momentum at half height:
.23*sqrt72
check that.
Answered by
Angela
what is sqrt??
Answered by
Rachel
Square Root
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