Asked by ARIANA
Pu-239 has a half-life of 24110 y. If 1.00 kg of this isotope is present in the used fuel rods of a nuclear power plant approximately how long will it take for this amount of Pu-239 to decay until there is less than 1 mg left ?
Please help. I do not know how to do this question.
Please help. I do not know how to do this question.
Answers
Answered by
DrBob222
k = 0.693/t<sub>1/2</sub>
Calculate k and substitute into the equation below.
ln(No/N) = kt
For No use 1000 g
For N use .001 g
k from above.
Solve for t in years.
Calculate k and substitute into the equation below.
ln(No/N) = kt
For No use 1000 g
For N use .001 g
k from above.
Solve for t in years.
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