Question

Please can someone help me solve this problem?

2/x + 6/x-1 less than or = -5

8/x -1 <= -5 Now add 1 to each side
8/x <= -4 so x must be < 0
Multiply both sides by x (a negative number). This means you have to change the direction of the >
8 >= -4x
Divide both sides by 4
2 >= -x
Multiply both sides by -1
-2 <= x < 0

thanks so much but can you please post the solution in integral notation for me

2 6
___ + ____ < or = - 5

X X - 1

I'm also not sure how you got 8x-1 I didn't know I could just add the two numerators if the denominators were different