What volume (in mL) of an 8% w/v acetic acid solution would be needed to form 2.2 L of carbon dioxide gas at 25.2 degrees Celsius and 0.9982 atm? Assume the acid is reacted with excess sodium bicarbonate, and round your final answer to two sig figs.

Answer 1

1. Write the equation and balance it.
2. Use PV = nRT and solve for n = moles CO2.
3. Using the equation #1, convert mols CO2 to moles acetic acid .
4. Convert mols acetic aci to grams. g = moles x molar mass.
5. With grams acetic acid you can go to the solution you have.
6. The soln is 8% w/v which means 8g acetic acid/100 mL soln.
7. How much of that do you need? That will be 100 mL x (g acetic acid needed/8) = ? mL.

Answer 2

0.090 mL

Answer 3

67ml