Question
What volume (in mL) of an 8% w/v acetic acid solution would be needed to form 2.2 L of carbon dioxide gas at 25.2 degrees Celsius and 0.9982 atm? Assume the acid is reacted with excess sodium bicarbonate, and round your final answer to two sig figs.
Answers
1. Write the equation and balance it.
2. Use PV = nRT and solve for n = moles CO2.
3. Using the equation #1, convert mols CO2 to moles acetic acid .
4. Convert mols acetic aci to grams. g = moles x molar mass.
5. With grams acetic acid you can go to the solution you have.
6. The soln is 8% w/v which means 8g acetic acid/100 mL soln.
7. How much of that do you need? That will be 100 mL x (g acetic acid needed/8) = ? mL.
2. Use PV = nRT and solve for n = moles CO2.
3. Using the equation #1, convert mols CO2 to moles acetic acid .
4. Convert mols acetic aci to grams. g = moles x molar mass.
5. With grams acetic acid you can go to the solution you have.
6. The soln is 8% w/v which means 8g acetic acid/100 mL soln.
7. How much of that do you need? That will be 100 mL x (g acetic acid needed/8) = ? mL.
0.090 mL
67ml
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