population after 4 years = 2950000(0.975)^4
= 2665879
or to the nearest 1000, 2667000
A city of 2,950,000 people has a 2.5% annual decrease in population. Determine the city's population after 4 years.
2 answers
the total decrease in population during fir5st year= 2950,000*2.5/100=73750
therefore, total decrease in population for 1 st year=2950,000-73750=2876250
total population in second year= 2876250
total decrease in population during the second year= 2876250*2.5/100=71906.25
therefore total decrease in population in second year=2876250-71906.25=2804343.8
total population for 3 rd year=2804343.8
total decrease in population in 3 rd year= 2804343.8*2.5/100=70108.594
therefore, total decrease in 3rd year=2804343.8-70108.594=2734235.2
total population for the fourth year=2734235.2
total decrease in population for fourth year=2734235.2*2.5/100=68355.88
total population decrease in fourth year=2734235.2-68355.88=2665879.3
thus correcting it to the nearest 1000 makes it 2,666,000
therefore, total decrease in population for 1 st year=2950,000-73750=2876250
total population in second year= 2876250
total decrease in population during the second year= 2876250*2.5/100=71906.25
therefore total decrease in population in second year=2876250-71906.25=2804343.8
total population for 3 rd year=2804343.8
total decrease in population in 3 rd year= 2804343.8*2.5/100=70108.594
therefore, total decrease in 3rd year=2804343.8-70108.594=2734235.2
total population for the fourth year=2734235.2
total decrease in population for fourth year=2734235.2*2.5/100=68355.88
total population decrease in fourth year=2734235.2-68355.88=2665879.3
thus correcting it to the nearest 1000 makes it 2,666,000
1 answer