Question
For the ionization of phenylacetic acid,
Hc8H7O2 +H20 <--> C8H7O2- (aq) + H3o+ (aq) Ka + 4.9x10^-5
What is the concentration of the phenylacetic ion, C8H702,- in 0.186 M phenylacetic acid, HC8H702?
Please explain the steps as well..thank you so much
Hc8H7O2 +H20 <--> C8H7O2- (aq) + H3o+ (aq) Ka + 4.9x10^-5
What is the concentration of the phenylacetic ion, C8H702,- in 0.186 M phenylacetic acid, HC8H702?
Please explain the steps as well..thank you so much
Answers
bobpursley
Ka=x^2/(.186-x)
x^2=4.9E-5(.186-x)
1/4.9E-5 x^2 +x -.186=0
use the quadratic equation.
x^2=4.9E-5(.186-x)
1/4.9E-5 x^2 +x -.186=0
use the quadratic equation.