Asked by Che
what is the percent ionization at equilibrium in a 0.31M solution of dimethylamine (Kb=4.2x10^-10) at 25 Celsius
Answers
Answered by
DrBob222
......CH3NH2 + H2O ==> CH3NH3^+ + OH^-
I.....0.31M..............0.........0
C.......-x...............x.........x
E.....0.31-x.............x.........x
Kb = (CH3NH3^+)(OH^-)/(CH3NH2)
Substitute the E line into the Kb expression and solve for x = (OH^-).
Then % ion = [(OH^-)/(CH3NH2)]*100
I.....0.31M..............0.........0
C.......-x...............x.........x
E.....0.31-x.............x.........x
Kb = (CH3NH3^+)(OH^-)/(CH3NH2)
Substitute the E line into the Kb expression and solve for x = (OH^-).
Then % ion = [(OH^-)/(CH3NH2)]*100
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.