Asked by Kelly
How would you analyze a solution known to contain Hg22+ and Cu2+?
Answers
Answered by
bobpursley
depends on what you mean "analyze".
Mercury I chloride is not soluble in water, whereas cupric chloride is.
Mercury I chloride is not soluble in water, whereas cupric chloride is.
Answered by
Kelly
calculate the specific rate constant
A] (mol/L) [B] (mol/L) Rate of appearance of C (mol/L-hr)
1.0 ×10^-2 1.0 0.30×10^−6
1.0 ×10^−2 3.0 8.10×10^−6
2.0 ×10^−2 3.0 3.24×10^−5
2.0 ×10^−2 1.0 1.20×10^−6
3.0 ×10^−2 3.0 7.30×10^−5
A] (mol/L) [B] (mol/L) Rate of appearance of C (mol/L-hr)
1.0 ×10^-2 1.0 0.30×10^−6
1.0 ×10^−2 3.0 8.10×10^−6
2.0 ×10^−2 3.0 3.24×10^−5
2.0 ×10^−2 1.0 1.20×10^−6
3.0 ×10^−2 3.0 7.30×10^−5
Answered by
DrBob222
It looks like the rate equation is
rate = k[A]<sup>2</sup>[B]<sup>3</sup> but the numbers are so scrunched it's difficult to make them out. You would do well to space them and the easy way to do that is with periods; i.e.,
1.0E-2...1.0...0.3E-6 etc.
To find k, use any trial, plug the concns of A and B into the rate equation I wrote and calculate k.
rate = k[A]<sup>2</sup>[B]<sup>3</sup> but the numbers are so scrunched it's difficult to make them out. You would do well to space them and the easy way to do that is with periods; i.e.,
1.0E-2...1.0...0.3E-6 etc.
To find k, use any trial, plug the concns of A and B into the rate equation I wrote and calculate k.
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