Asked by Dakeva
is the value 3pi/2 is a solution for the equation 2sin^2x-sinx-1=0
Answers
Answered by
Damon
sin 3 pi/2 = -1
2(-1)^2 -(-1) -1
2 + 1 - 1
2
Looks like a typo to me. Perhaps it should be
2 sin^2x + sinx - 1 = 0
2(-1)^2 -(-1) -1
2 + 1 - 1
2
Looks like a typo to me. Perhaps it should be
2 sin^2x + sinx - 1 = 0
Answered by
You welcome
False
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