Question
3.0 moles each of carbon monoxide, hydrogen, and carbon are placed in a 2.0 liter vessel and allowed to come to equilibrium according to the equation: CO(g)+H2(g)-->C(s)+H20(g)
if the equilibrium constant at the temperature of the experiment is 4.0, what is the equilibrium concentration of water vapor?
if the equilibrium constant at the temperature of the experiment is 4.0, what is the equilibrium concentration of water vapor?
Answers
3.0 mols/2.0 L = 1.5M
..........CO + H2 ==> C + H2O
initial..1.5..1.5....1.5...0
change....-x...-x.....x....x
equil...1.5-x..1.5-x..x....x
Kc = 4.0 = (H2O)/(C0)(H2O)
Substitute from the ICE chart into the Kc expression and solve for x.
..........CO + H2 ==> C + H2O
initial..1.5..1.5....1.5...0
change....-x...-x.....x....x
equil...1.5-x..1.5-x..x....x
Kc = 4.0 = (H2O)/(C0)(H2O)
Substitute from the ICE chart into the Kc expression and solve for x.
[H2O]=.81
[H2O]=1M
H2O = 9M
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