Two vectors and have magnitude = 3.08 and = 3.08. Their vector product is = -5.07 + 2.00 . What is the angle between and

Answer 1

Your vector product should contain unit vectors, such as i and k.
-5.07 +2.00 is just -3.07

You can get the angle between the 3.08 vectors from the magnitude of the vector product. That magnitude appears to be 5.45.
sinA = 3.08^2/5.45^2 = 0.3194
A = 18.6 degrees

Answer 2

i forgot to put thanks a lot for your time