Asked by Jules
how many grams of ZnCl2 are needed to prepare 250 ml of an aqueous solution with an osmolarity equal to 0.300?
Answers
Answered by
DrBob222
An osmolarity of 0.3 osm = 0.1M ZnCl2 (since there are three particles in a molecule of ZnCl2).
You wnat how many mole? That is M x L = ?
The moles ZnCl2 = grams ZnCl2/molar mass.
You wnat how many mole? That is M x L = ?
The moles ZnCl2 = grams ZnCl2/molar mass.
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