Question
Zn + HCl --> ZnCl2 + H2
If 18 grams of Zn are used in the following reaction, how many grams of H2 will be produced?
If 18 grams of Zn are used in the following reaction, how many grams of H2 will be produced?
Answers
Jai
first let's see if the chemical equation is balanced.
Zn + HCl --> ZnCl2 + H2
since not yet balanced, then we balance it :P
Zn + 2HCl --> ZnCl2 + H2
since we are given grams of Zinc, we need to find the mass of Zn from periodic table to convert it to moles. thus
Zn = 65.4 g/mol
also since we are required to find grams of H2, we look also for the mass of H:
H = 1 , thus
H2 = 1*2 = 2 g/mol
therefore,
18 g Zn * (1 mol Zn / 65.4 g Zn) * (1 mol H2 / 1 mol Zn) * (2 g H2 / 1 mol H2) = 0.55 g H2
hope this helps~ :)
Zn + HCl --> ZnCl2 + H2
since not yet balanced, then we balance it :P
Zn + 2HCl --> ZnCl2 + H2
since we are given grams of Zinc, we need to find the mass of Zn from periodic table to convert it to moles. thus
Zn = 65.4 g/mol
also since we are required to find grams of H2, we look also for the mass of H:
H = 1 , thus
H2 = 1*2 = 2 g/mol
therefore,
18 g Zn * (1 mol Zn / 65.4 g Zn) * (1 mol H2 / 1 mol Zn) * (2 g H2 / 1 mol H2) = 0.55 g H2
hope this helps~ :)