Asked by Annoymous
A particle is projected vertically upwards from ground level with an initial velocity of 34.94m/s. Neglecting air resistance, calculate the total time taken, in seconds, for the particle to hit the ground again.
Take the magnitude of the acceleration due to gravity to by 9.81m/s^2.
Take the magnitude of the acceleration due to gravity to by 9.81m/s^2.
Answers
Answered by
Damon
Find the time to the top and double it.
v = Vi - g t
at the top, v = 0
0 = 34.9 - 9.81 t
t = 34.9/9.81
2 t = 2 * 34.9/9.81
v = Vi - g t
at the top, v = 0
0 = 34.9 - 9.81 t
t = 34.9/9.81
2 t = 2 * 34.9/9.81
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