Question

If someone could please be kind enough to see me through this problem?

Calculate the value of Kp for the equation C(s) + CO2(g) <--> 2CO(g) Kp?

Given that at a certain temperature..
C(s) + 2H2O(g) <--> CO2(g) + 2H2(g) Kp1 = 3.03 and
H2(g) + CO2(g) <--> H2O(g) + CO(g) Kp2 = 0.637

i sq rooted the last equation: (0.637)^2 = 0.405769 and then multiplied by 3.03 = 1.2294
is that correct?

Answer 1

I think what you want to do is multiply equation 1 by 2 and add to equation 2. I believe that will give you the equation you want. To find the Kp value, it will be (Kp1)^2*Kp2 = ?

Answer 2

Hi Dr. Bob,
(3.03)^2 * 0.637 = 5.85?
What would I do with the first equation that i got?

Answer 3

OHH (2.567)^2*0.637 = 4.197?!

.. or was that a fail epiphany

Answer 4

If I take the square root of 3.03*0.637 I don't get 4.197.

Answer 5

is this answer correct? these form need to verify is these answers are correct. ty