Question

A stock solution was prepared by dissolving exactly 0.4000 g of pure ASA (180.16g/mol) in 10.00 mL of NaOH and heating the solution to a gentle boil. After cooling to room temperature, the solution was poured into a 250 ml volumetric flask and diluted to the mark with DI water. Calculate the concentration of ASA in the flask.

Answer 1

concn ASA = mols/L
0.4000 g ASA x (1 mol ASA/molar mass ASA) = mols.