Question

If 2.29 mL of a stock solution of acetic acid with a concentration of 0.723 M is mixed with 15.75 mL of water, what is the concentration of the diluted solution?
volume to start = 2.29
volume added = 15.75
total volume = ?
0.723M x (2.29/total volume) = ?
Note: This assumes volumes are additive; technically they are not but in dilute solutions like this the are for all practical purposes (still not technically)

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