Asked by Sarah
How far above the surface of Earth would you weigh 63.6 percent of your surface weight?
Answers
Answered by
Steve
If the new radius is R, and the earth's radius is r,
.636 * Mmg/r^2 = = Mmg/R^2
.636/r^2 = 1/R^2
R = r/.797 = 1.25r
plug in your favorite value for r, and figure the difference
.636 * Mmg/r^2 = = Mmg/R^2
.636/r^2 = 1/R^2
R = r/.797 = 1.25r
plug in your favorite value for r, and figure the difference
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