Asked by Anonymous
a ball of radius 5cm is hung against the wall with an 8cm rope from one side of the ball.it has mass of 60newtons.fined the tension in the rope and the reaction at the wall.
Answers
Answered by
drwls
The weight (not the mass) of the ball is 60N.
The center of the ball, the point of wall contact and the rope support point at the wall form a 5-12-13 right triangle. Draw the figure to convince yourself. Remember that the rope is attached to the near side of the ball.
The tension force T is balanced by a horizontal component (5/12)*T at the wall and the vertical weight force of 12/13 T = 60 N
T = (13/12)*60 = 65 N
Wall compressive force = (5/13)*65 = 25 N
The center of the ball, the point of wall contact and the rope support point at the wall form a 5-12-13 right triangle. Draw the figure to convince yourself. Remember that the rope is attached to the near side of the ball.
The tension force T is balanced by a horizontal component (5/12)*T at the wall and the vertical weight force of 12/13 T = 60 N
T = (13/12)*60 = 65 N
Wall compressive force = (5/13)*65 = 25 N
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