Asked by Lucy
The problem is 5x to the 3rd times (7x)squared.
I multiplied (7x)(7x) first and got x squared + 14x + 49. Then I multiplied each of those by 5x to the 3rd and came up with an answer of: 5x to the 5th + 70x to the 4th + 245x to the 3rd. Did I get this one correct??
I multiplied (7x)(7x) first and got x squared + 14x + 49. Then I multiplied each of those by 5x to the 3rd and came up with an answer of: 5x to the 5th + 70x to the 4th + 245x to the 3rd. Did I get this one correct??
Answers
Answered by
drwls
<<I multiplied (7x)(7x) first and got x squared + 14x + 49.>>
Well you did that wrong, as well as some other steps.
(7x)^2 = 49x^2
The polynomial you wrote is (x+7)^2
5x^3*(7x)^2 = 5*49 x^5 = 245 x^5
Well you did that wrong, as well as some other steps.
(7x)^2 = 49x^2
The polynomial you wrote is (x+7)^2
5x^3*(7x)^2 = 5*49 x^5 = 245 x^5
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.