The center placed in the point (0,0)
radius = sqrt ( 36 ) = 6
x^2+y^2=36 is a circle. How can you tell without actually plotting? Where is the center?
2 answers
ya gotta know that
(x-h)^2 + (y-k)^2 = r^2
is the equation for a circle of radius r with center at (h,k)
(x-h)^2 + (y-k)^2 = r^2
is the equation for a circle of radius r with center at (h,k)