Asked by Maddie
FInd the area of the region bounded by the graphs of y= 3x^2+1 , y=0, x=-2.7, x=2.5
Answers
Answered by
MathMate
Make a sketch of the functions and you'll find that the area resembles two triangles whose total area is about 40.
Area =
∫(3x^2+1-0)dx for x from -2.7 to 2.5
I get 40.5 approx.
Area =
∫(3x^2+1-0)dx for x from -2.7 to 2.5
I get 40.5 approx.
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