A Ferris wheel rotates 4 times each minute and has a diameter of 17 m.

The acceleration of gravity is 9.8 m/s2. What is the centripetal acceleration of a rider?
Answer in units of m/s2

2 answers

The centripetal acceleration does not depend upon g or the position on the wheel (top, bottom side etc.)

It equals V^2/R

In this case,
V = pi*17m/15s = 3.56 m/s
R = 17/2 = 8.5 m

Now compute V^2/R for the answer.
Thank You!!!