i still understand this problem
If x^2/25 +y^2/49=1 and y(3)=5.6000, find y'(3) by implicit differentiation.
4 answers
i mean i still don't understand this problem
I got that!
Use implicit differentiation, which is actually derived from the chain rule, except that when it comes to dy/dx, since y is not know, we simply write dy/dx, or y'.
df(y)/dx = df(y)/dy * dy/dx
x^2/25 +y^2/49=1
Differentiate both sides:
2x/25 + 2y/49 * dy/dx = 0
(dy/dx = y'(x))
y'(x)=-(2x/25)*(49/2y)
=-(49x/25y)
y(3)=5.6 => x=3, y=5.6
y'(3)= -(49(3))/(25(5.6))
= -147/140
= -21/20
Use implicit differentiation, which is actually derived from the chain rule, except that when it comes to dy/dx, since y is not know, we simply write dy/dx, or y'.
df(y)/dx = df(y)/dy * dy/dx
x^2/25 +y^2/49=1
Differentiate both sides:
2x/25 + 2y/49 * dy/dx = 0
(dy/dx = y'(x))
y'(x)=-(2x/25)*(49/2y)
=-(49x/25y)
y(3)=5.6 => x=3, y=5.6
y'(3)= -(49(3))/(25(5.6))
= -147/140
= -21/20
thanks
You're welcome! :)
1 answer