Question

i still understand this problem
If x^2/25 +y^2/49=1 and y(3)=5.6000, find y'(3) by implicit differentiation.

Answer 1

i mean i still don't understand this problem

Answer 2

I got that!

Use implicit differentiation, which is actually derived from the chain rule, except that when it comes to dy/dx, since y is not know, we simply write dy/dx, or y'.

df(y)/dx = df(y)/dy * dy/dx

x^2/25 +y^2/49=1
Differentiate both sides:
2x/25 + 2y/49 * dy/dx = 0
(dy/dx = y'(x))
y'(x)=-(2x/25)*(49/2y)
=-(49x/25y)
y(3)=5.6 => x=3, y=5.6
y'(3)= -(49(3))/(25(5.6))
= -147/140
= -21/20

Answer 3

thanks

Answer 4

You're welcome! :)