Question
Use Lagrange multipliers to find the max/min values of the function f(x,y)=xy subject to the constraint: x^2/8+y^2/2 =1
so I compare the gradient vectors of both f(x,y) and the constraint:
<y,x>=L<x/4,Ly>
resulting in y=Lx/4 and x=Ly
now how do i solve for L x and y??? Please help this is so confusing for me? Im completely lost here!!
so I compare the gradient vectors of both f(x,y) and the constraint:
<y,x>=L<x/4,Ly>
resulting in y=Lx/4 and x=Ly
now how do i solve for L x and y??? Please help this is so confusing for me? Im completely lost here!!
Answers
L should be eliminated using the first two equations involving partial derivatives.
See other response.
See other response.
Related Questions
"Using Lagrange multipliers, find the minimum value of f(x,y) = x^2 + y subject to the constraint x^...
Use Lagrange multipliers to find the max/min values of the function f(x,y)=xy subject to the constra...
Use lagrange multipliers to find the max and min values of the func f(x,y)=xy subject to the constra...