Asked by Abby

What volume of aluminum would be needed to balance a 1.00 cm^3 sample of copper on a 2 pan laboratory balance?
Answered by Damon
density Al * volume Al = density Cu * 1 cm^3

make sure density of Al is in g/cm^3
Answered by Abby
I literally have no idea what this means. Do I do both sides and divide one side? This is confusing.
Answered by Damon
You must look up the densities of Al and Cu
then your answer is
Volume of Al = (density CU/densityAL) *1 cm^3
Answered by Damon
Vol of Al = (8.9/2.7)*1
= 3.3 cm^3 of Al
Answered by Abby
Yay! I got the same answer, and I tried to figure it out before you answered. Good. That makes me happy. Thank you!
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