Asked by Sharma
iron cube of side 10 cm is kept on a horizontal table . If the density of iron cube is 8000 kg /m cube , find the pressure on the portion of the table where the cube is kept?
Answers
Answered by
bobpursley
weight= mg=8000kg/m^3 * (.1m)^3
pressure= force/area=mg/(.1)^2=
= 8000kg*9.8N/kg*.1 N/m^2
pressure= force/area=mg/(.1)^2=
= 8000kg*9.8N/kg*.1 N/m^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.