Asked by Grant
A farmer with 700 ft of fencing wants to enclose a rectangular area and then divide it into four pens with fencing parallel to one side of the rectangle. What is the largest possible total area of the four pens?
Answers
Answered by
Grant
Answer is 12250
Answered by
Steve
so, is there a question somewhere in there?
Answered by
MathMate
What is the largest possible total area of the four pens?
Let x=shorter side of the big rectangle.
and y=long side of the big rectangle
Fence required = 5x+2y=700 => y=350-5x/2
Total area of pens
A=xy
=x(350-5x/2)
To get the maximum area, we equate dA/dx=0
dA/dx = 350-5x = 0, or
x=70
y=350-5x/2 = 175
Maximum total area=xy=70*175=12250'
Let x=shorter side of the big rectangle.
and y=long side of the big rectangle
Fence required = 5x+2y=700 => y=350-5x/2
Total area of pens
A=xy
=x(350-5x/2)
To get the maximum area, we equate dA/dx=0
dA/dx = 350-5x = 0, or
x=70
y=350-5x/2 = 175
Maximum total area=xy=70*175=12250'
Answered by
Tina
Can someone draw the picture?
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