A farmer with 700 ft of fencing wants to enclose a rectangular area and then divide it into four pens with fencing parallel to one side of the rectangle. What is the largest possible total area of the four pens?
4 answers
Answer is 12250
so, is there a question somewhere in there?
What is the largest possible total area of the four pens?
Let x=shorter side of the big rectangle.
and y=long side of the big rectangle
Fence required = 5x+2y=700 => y=350-5x/2
Total area of pens
A=xy
=x(350-5x/2)
To get the maximum area, we equate dA/dx=0
dA/dx = 350-5x = 0, or
x=70
y=350-5x/2 = 175
Maximum total area=xy=70*175=12250'
Let x=shorter side of the big rectangle.
and y=long side of the big rectangle
Fence required = 5x+2y=700 => y=350-5x/2
Total area of pens
A=xy
=x(350-5x/2)
To get the maximum area, we equate dA/dx=0
dA/dx = 350-5x = 0, or
x=70
y=350-5x/2 = 175
Maximum total area=xy=70*175=12250'
Can someone draw the picture?
1 answer