Asked by Grant
                A farmer with 700 ft of fencing wants to enclose a rectangular area and then divide it into four pens with fencing parallel to one side of the rectangle. What is the largest possible total area of the four pens?
            
            
        Answers
                    Answered by
            Grant
            
    Answer is 12250
    
                    Answered by
            Steve
            
    so, is there a question somewhere in there?
    
                    Answered by
            MathMate
            
    What is the largest possible total area of the four pens?
Let x=shorter side of the big rectangle.
and y=long side of the big rectangle
Fence required = 5x+2y=700 => y=350-5x/2
Total area of pens
A=xy
=x(350-5x/2)
To get the maximum area, we equate dA/dx=0
dA/dx = 350-5x = 0, or
x=70
y=350-5x/2 = 175
Maximum total area=xy=70*175=12250'
    
Let x=shorter side of the big rectangle.
and y=long side of the big rectangle
Fence required = 5x+2y=700 => y=350-5x/2
Total area of pens
A=xy
=x(350-5x/2)
To get the maximum area, we equate dA/dx=0
dA/dx = 350-5x = 0, or
x=70
y=350-5x/2 = 175
Maximum total area=xy=70*175=12250'
                    Answered by
            Tina
            
    Can someone draw the picture?
    
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