assuming the x side is parallel to the wall, then
2x+4y = 120
The area is
2xy = 2x(120-2x)/4 = 60x - x^2
The maximum area is thus where x=30
As usual with such problems, the maximum area is achieved when the fencing is divided equally among lengths and widths.
a farmer has 120 m of fencing to make two identical rectangular enclosures using an existing wall as one side of each enclosure. The dimensions of each closure are x metres and y metres as shown. Obtain and expression in terms of x only for the total area of two enclosures, and calculate the maximum value of the area. I"m really stuck please help!
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