Evaluate the integral S x/(sqrt(3x-1))dx
Use U-Substitution method.
2 answers
s=xsqrt
Let u^2 = 3x-1
2u du = 3 dx
and the integrand then becomes
(u^2+1)/u * 2u/3 du = 2/3 (u^2+1) du
Integrate that and then change back to x.
2u du = 3 dx
and the integrand then becomes
(u^2+1)/u * 2u/3 du = 2/3 (u^2+1) du
Integrate that and then change back to x.