How about
(1/3)(x^2 - 200) / √(x^2 + 100)
I checked it by differentiating it.
Evaluate:
integral x^3/[sqrt*(x^2+100)]dx
can someone tell me what they get as a final answer..I've been going at this for hours and don't get the answer in the back of the textbook
2 answers
there should be no division, I copied the verification, silly me
go with (1/3)(x^2 - 200)√(x^2 + 100)
which btw is what "helper" also had in the other post.
go with (1/3)(x^2 - 200)√(x^2 + 100)
which btw is what "helper" also had in the other post.