Asked by krystal
Calculate the molarity of each.
a. 1.50 mole of NaCl in 8.00 L of solution
0.188 M NaCl
b. 270 mg of NaCl in 3.00 mL of solution
90 M NaCl
a. 1.50 mole of NaCl in 8.00 L of solution
0.188 M NaCl
b. 270 mg of NaCl in 3.00 mL of solution
90 M NaCl
Answers
Answered by
DrBob222
I agee with a but not b.
b)
270 mg = 0.270g
mols = 0.270/58.44 = about 0.005
M = moles/L = about 0.005/0.003 = ?
b)
270 mg = 0.270g
mols = 0.270/58.44 = about 0.005
M = moles/L = about 0.005/0.003 = ?
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