Asked by john
jasmine bought 26 pieces of fruit.she bought 6 oranges.she bought twice as many apples as oranges,and twice as many oranges as bananas.she also bought some pears.
Answers
Answered by
MathMate
Please complete the question.
Answered by
Siddique Ahmed
Total Fruit = 26
as per condition
O = 6 => O = 6
A = 2O => A = 2.6 => A = 12
O = 2B => B = O/2 => B = 6/2 => B = 3
O+A+B = 6+12+3 => O+A+B = 21
P = T.F - (O+A+B) => P= 26 - 21 => P=5
as per condition
O = 6 => O = 6
A = 2O => A = 2.6 => A = 12
O = 2B => B = O/2 => B = 6/2 => B = 3
O+A+B = 6+12+3 => O+A+B = 21
P = T.F - (O+A+B) => P= 26 - 21 => P=5
Answered by
Cherise
We have six oranges.
Apples= 6x2
Banana = 6/2
Pears: 26- (apple+bananas + oranges)
Pears = 26-21
Pears: 5
Basically, this is really easy. I know it's 2021, about a decade later, but this is for anyone else who sees this problem. It's actually from a fourth-grade state test, released questions. The state test occurred in 2005.
Apples= 6x2
Banana = 6/2
Pears: 26- (apple+bananas + oranges)
Pears = 26-21
Pears: 5
Basically, this is really easy. I know it's 2021, about a decade later, but this is for anyone else who sees this problem. It's actually from a fourth-grade state test, released questions. The state test occurred in 2005.
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