Asked by Kayla
Two small charged balls have a repulsive force of 0.12 N when they are separated by a distance of 0.85 m. The balls are moved closer together, until the repulsive force is 0.60 N. How far apart are they now?
Answers
Answered by
drwls
For the repulsive force to increase by a factor of 5, the distance must decrease by a factor of sqrt5 = 2.236
That would make the new distance 0.380 m
That would make the new distance 0.380 m
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