let y = (x^2 + sinx)/cosx
by quotient rule....
dy/dx = ( cosx(2x + cosx) - sinx(x^2 + cosx) )/cos^2 x
simplify if needed.
I need help finding the derivative of
(x^2+sinx)secx
3 answers
there is no quotient it is multiplication
I changed secx to 1/cosx
however, if you insist on using the product rule
dy/dx = (x^2 + sinx)(tan^2 x) + (2x + cosx)(secx)
illustrating that there is often more than one way to express the same result.
however, if you insist on using the product rule
dy/dx = (x^2 + sinx)(tan^2 x) + (2x + cosx)(secx)
illustrating that there is often more than one way to express the same result.
3 answers