Question

I need help finding the derivative of
(x^2+sinx)secx

Answer 1

let y = (x^2 + sinx)/cosx

by quotient rule....
dy/dx = ( cosx(2x + cosx) - sinx(x^2 + cosx) )/cos^2 x

simplify if needed.

Answer 2

there is no quotient it is multiplication

Answer 3

I changed secx to 1/cosx

however, if you insist on using the product rule

dy/dx = (x^2 + sinx)(tan^2 x) + (2x + cosx)(secx)

illustrating that there is often more than one way to express the same result.