Asked by Annie
I need help finding the derivative of
√3x/(x^2-4) at x=3
√3x/(x^2-4) at x=3
Answers
Answered by
Steve
y = √(3x)/(x^2-4)
y' =
-√3(3x^2+4)
------------------
2√x (x^2-4)^2
At x=3 that is
-√3(31)/(2√3 (25)) = -31/50
y' =
-√3(3x^2+4)
------------------
2√x (x^2-4)^2
At x=3 that is
-√3(31)/(2√3 (25)) = -31/50
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